2x^2+35+43x+25=180

Solution for 2x^2+35+43x+25=180 equation:

2x^2+35+43x+25=180

We move all terms to the left:

2x^2+35+43x+25-(180)=0

We add all the numbers together, and all the variables

2x^2+43x-120=0

a = 2; b = 43; c = -120;
Δ = b2-4ac
Δ = 432-4·2·(-120)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2809}=53$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(43)-53}{2*2}=\frac{-96}{4}
=-24
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(43)+53}{2*2}=\frac{10}{4}
=2+1/2
$